2(x^2+2x+2)=0

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Solution for 2(x^2+2x+2)=0 equation: 



2(x^2+2x+2)=0

We multiply parentheses

2x^2+4x+4=0

a = 2; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·2·4
Δ = -16
Delta is less than zero, so there is no solution for the equation

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